LINKAGE: violates “independent assortment”
1/22/92, rvsd 1/26/94, 1/19/96, 1/22/97, 1/23/98, 19 Jan 00, 19 Jan 01, 21 Jan 04, 19Jan05, 24Jan08
SGML p. 95-, GMSLG: p. 123-, 7th: pp 142-153, 9th: 129-140
Exceptions (violations) of Mendelian-predicted behavior can yield new insights
Bateson and Punnett studying sweet pea,
cross: PP.LL x pp.ll phenotype expected: observed
Purple/white, Long/round grains: PL 3911 4831
PL x pl: PpLl (p 142), then selfed Pl 1303 390
F2 (selfing) did not produce 9:3:3:1 pL 1303 393
ratio: (note excess of parental types) pl 435 1338
postulated “coupling” Total: 6952
Morgan found similar prob in Drosophila (purple eyes, vestigial wings x w.t.),
introduced test cross technique
page 131: pr/pr.vg/vg x pr+/pr+.vg+/vg+. F1: pr/pr+.vg/vg+ (then crossed times pr/pr.vg.vg)
TEST CROSSED: (notation: + = wildtype) phenotype expected: observed
allows direct analysis of genotype of parent ++ 710 1339
(use doubly homozygous recessive) pr vg 710 1195
should get 1:1:1:1 if independent, got: + vg 710 151
(excess of parental types)(p. 142) pr + 710 154
Total: 2839
Morgan postulated both genes on same chromosome, segregate together (violated Mendel’s 2nd law)
If genes are located on same chromosome, how do they separate, as in the rare progeny above?
RECOMBINATION: meiosis generates 1N genotype different from either of parental 1N genotypes.
Evidence: Can be seen as chiasmata, mark exchanges between non-sister homologous chromosomes
Note difference between interchromosomal recombination: same as Mendel’s independent assortment
intrachromosomal recombination: by recombination
“Recombinant type” phenotype defined as one trait from one parent, one trait from other parent
Recombination frequency: (total recombinant events/total progeny) = distance between in %
Interchromosomal freq = 50% (25% of each recombinant type in test cross)
Intrachromosomal freq = <50% zB: fr Morgans expt: (151 + 154)/2839 (total) = 0.107, (10.7 %)
Seen as chiasmata during meiosis
[2008: OMIT?:
Linkage of genes on X chromosome easier than autosomal:
male is hemizygous, his phenotype = genotype
(y = yellow body) (+ = brown) / (+ = red eye) (w = white eye) P: yw+/yw+ fem x y+w/Y male
zB: heterozygous female x male phenotype expected: observed
will produce sons reflecting females genotype: yw: 1128 43
Drosophila: y+w 1128 2146
yw+ 1128 2302
y+w+ 1128 22
Count only males: total 4513
F1: yw+/y+w x yw+/Y: rec freq: (43 + 22)/4513 = 1.4%
LINKAGE MAPS: (p 129 and 139)
Sturtevant (undergrad student of Morgan) proposed linear relationship on chromosome:
greater distance loci, more prob of cross over:
genetic map unit = distance producing 1% recombinants.